$$\begin{aligned} &\frac{d m}{d t}=-p_{g} m+p_{3} m_{e 2}\\ &\frac{d m_{e 2}}{d t}=p_{g} m-p_{2} m_{e 2}-p_{3} m_{e 2}=p_{g} m-\left(p_{2}+p_{3}\right) m_{e 2} \end{aligned}$$ [mathjax] $$\frac{d}{d t}\left[\begin{array}{ccc} m \\ m_{e 2} \end{array}\right]=\left[\begin{array}{ccc} -p_{g} & p_{3} \\ p_{g} & -\left(p_{2}+p_{3}\right) \end{array}\right]\left[\begin{array}{ccc} m \\ m_{e 2} \end{array}\right]$$ 方程的解为\(  \left[\begin{array}{cc} m \\ m_{e…